jcmoore33 jcmoore33
  • 21-05-2018
  • Mathematics
contestada

the law of cosines is a2+b2-2abcosC=c2 find the value of 2abcosC

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11beehshahbaz 11beehshahbaz
  • 21-05-2018
Isolating 2abCos(c) on one side of the equation and using the given values of a, b and c we can find the answer to this question as shown below:

[tex] a^{2} + b^{2} -2ab*cos(C)=c^{2} \\ \\ 2ab *cos(C)= a^{2} + b^{2} - c^{2} \\ \\ 2ab *cos(C)=2^{2} + 2^{2}- 1^{2} \\ \\ 2ab*cos(C) = 7 [/tex]
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Diamond1011
Diamond1011 Diamond1011
  • 21-05-2018
2ab * cos (C)= 7

hope this helps you
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