The correct answer is B.
Start from the equation for the circumference and solve it for the radius:
[tex] C = 2\pi r \implies r = \frac{C}{2\pi} [/tex]
So, the radius of the circumference is
[tex] \frac{6\pi}{2\pi} = 3 [/tex] inches
Once the radius in known, you can plug it in the formula for the area:
[tex] A = \pir^2 = 9\pi [/tex] squared inches.
