A(-2, 2), B(4, 2), C(-6, -1), D(0, -1)
AB = CD = 4 - (-2) = 4 + 2 = 6
BD = AC. Use the formula of a distance between two points:
[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
Substitute the coordinates of the points B and D:
[tex]d=\sqrt{(-1-2)62+(0-4)^2}=\sqrt{(-3)^2+(-4)^2}=\sqrt{9+16}=\sqrt{25}=5[/tex]
BD = AC = 5
The perimeter of parallelogram ABCD:
P = 2 · 6 + 2 · 5 = 12 + 10 = 22
Answer: a. 22 units.
