louisehaley louisehaley

18-02-2019
Mathematics

contestada

PLEASE HELP! Trigonometry question :(

PLEASE HELP Trigonometry question class=

Respuesta :

jimrgrant1 jimrgrant1

18-02-2019

Answer:

see explanation

Step-by-step explanation:

Using the sine ratio

sinA = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{k}{c}[/tex]

sinC = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{k}{a}[/tex]

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