Answer:
D
Step-by-step explanation:
Using the rule of exponents
[tex](a^nb^n)^{m}[/tex] = [tex]a^{(mn)}[/tex][tex]b^{(mn)}[/tex], hence
([tex]a^{\frac{1}{2} }[/tex][tex]b^{\frac{1}{3} }[/tex])^([tex]\frac{1}{2}[/tex])
= [tex]a^{\frac{1}{2}(\frac{1}{2} ) }[/tex] × [tex]b^{\frac{1}{3}(\frac{1}{2}) }[/tex]
= [tex]a^{\frac{1}{4} }[/tex] [tex]b^{\frac{1}{6} }[/tex] → D
