Answer: c. area ≈ 5 units²
Step-by-step explanation:
Step 1: Use Law of Sines to find b:
[tex]\dfrac{sinC}{c}=\dfrac{sinB}{b}\\\\\\\dfrac{sin44.9}{4}=\dfrac{sin107.3}{b}\\\\\\b=\dfrac{4sin107.3}{sin44.9}\\\\\\b=5.4[/tex]
Step 2: Use SAS formula to find the area of the triangle:
[tex]Area = \dfrac{1}{2}bcsinA\\\\\\Area=\dfrac{1}{2}(5.4)(4)sin27.8\\\\\\Area = 5.05[/tex]
