yipyip
yipyip
16-05-2016
Chemistry
contestada
Determine the pH of a 5x10^-4 M solution of Ca(OH)2
Respuesta :
Willchemistry
Willchemistry
22-05-2016
Ca(OH)₂ ==> Ca²⁺ + 2 OH
-
Ca(OH)
₂ is
strong Bases
Therefore, the [OH-] equals 5 x 10⁻⁴ M. For every Ca(OH)₂ you produce 2 OH⁻
.
pOH = - log[ OH⁻]
pOH = - log [
5 x 10⁻⁴ ]
pOH = 3.30
pH + pOH = 14
pH + 3.30 = 14
pH = 14 - 3.30
pH = 10.7
hope this helps!
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