Sara leaves home at 7am traveling at a rate of 45 mi/h. her son discovers that she has forgotten her briefcase and starts out to catch up with her. her son leaves at 7:30 am traveling at a rate of 55 mi/h. At what time will he over take his mother?
Sara 45 mph Son 55 mph Sara 07:00 Son 07:30 Difference in time= 00:30 => 0.50 hours Sara will have covered 22.50 miles Son starts
catch up distance= 22.50 miles catch up speed = 55 -45 catch up speed = 10 mph Catchup time = catchup distance/catch up speed catch up time= 2.25 catch up time= 2.25 hours They will meet at 9:55 am mph
