Answer:
x=5+√17 or 5-√17
Step-by-step explanation:
Given the equation x²-10x+25=17 we first make the equation to be in the form
ax²+bx+c=0.
Therefore, we cross 17 to the other side.
x²-10x+25-17=0
x²-10x+8=0
If we substitute the coefficients in the quadratic formula we get:
x=(-b±[tex]\sqrt{b^{2}-4ac }[/tex])/2a
=(10±[tex]\sqrt{(-10)^{2}-(4*1*8)}[/tex])/(2×1)
x=5+√17 or 5-√17
Answer:
Square root of 17, plus 5
Negative square root of 17, plus 5
Step-by-step explanation:
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