neilanymarquez1209
neilanymarquez1209 neilanymarquez1209
  • 18-10-2019
  • Mathematics
contestada

Determine the equations of the asymptotes: g(x)= [tex]\frac{2x^2+1}{x+3}[/tex]

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sqdancefan
sqdancefan sqdancefan
  • 18-10-2019

Answer:

  • x = -3
  • y = 2x -6

Step-by-step explanation:

The vertical asymptote is found where the denominator is zero, at x = -3.

The slant asymptote is the quotient of the division: 2x -6.

  g(x) = (2x^2+1)/(x +3)

  g(x) = 2x -6 +19/(x+3)

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