kenya4
kenya4
16-06-2016
Mathematics
contestada
the vertex of the graph of y=(x-1)^2-5 is
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hartnn
hartnn
16-06-2016
for y = (x-h)^2 + k
the vertex is h,k
comparing
y=(x-1)^2-5
with y = (x-h)^2 + k
we have h = 1, k = -5
so the vertex of y=(x-1)^2-5 is (1,-5)
Answer Link
th3ax3lord
th3ax3lord
07-06-2019
Answer:
(1,-5)
Step-by-step explanation:
Answer Link
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