The complete square will be [tex](x-3)^{2}[/tex] = 3
Step-by-step explanation:
Given,
[tex]2x^{2} -12x+12=0[/tex]
or, [tex]x^{2} -6x+6=0[/tex] [ by eliminating 2 from both the sides]
To make it square
[tex]x^{2} -6x+6=0[/tex]
or, [tex]x^{2} -2xX3+9-9+6=0[/tex] [ [tex](a+b)^{2}=a^{2} +2ab+b^{2}[/tex]
or, [tex](x-3)^{2}[/tex] = 9-6
or, [tex](x-3)^{2}[/tex] = 3
Hence the correct option is B
