Answer:
884.8 mL
Explanation:
If we have STP condition (Standard temperature and pressure), we will have the following relationship:
[tex]1~mol=22.4~L[/tex] or [tex]1~mol=22400~mL[/tex]. With this in mind we can do the conversion:
[tex]0.0395~mol\frac{22400~mL}{1~mol}=884.8~mL[/tex]
In the 0.0395 mol of fluorine gas, we will have 884.8 mL of gas at STP conditions.
