Answer:
(a, b, c) = (12, 2, 11)
Step-by-step explanation:
We assume you want to simplify ...
[tex]\dfrac{(x^5yz^4)^3}{x^3yz}=x^{3\cdot 5-3}y^{3\cdot 1-1}z^{3\cdot 4-1}=x^{12}y^2z^{11}[/tex]
Compared to (x^a)(y^b)(z^c), we find that ...
(a, b, c) = (12, 2, 11)
_____
The applicable rules of exponents are ...
(a^b)^c = a^(bc)
(ab)^c = (a^c)(b^c)
(a^b)/(a^c) = a^(b-c)
