A non-ideal battery has a 6.0-V emf and an internal resistance of 0.6 l. Determine the terminal voltage (in volts) when the current drawn from the battery is 1.0 A

Respuesta :

V=I x R = i.0 A x 0.6 ohms = 0.6 volts term = battery V -- int V
=6,0 --0.6 =5.4 volts terminal volts 5.4 volts