Answer:
30 m/min² (= 0.0833 m/s²)
Step-by-step explanation:
Initially,
Distance ran = 100 m
Time taken = 10 min
Average speed = Distance ran ÷ Time taken
= 100 ÷ 10
= 10 m/min
Hence here initial speed = 10 m/min
Given that her final speed was 15 m/min
her change in speed = 15 - 10 = 5 m / min
We are also given that this change in speed took 10 seconds = 1/6 min
Recall that by definition, acieration = rate of change of speed
= change in speed ÷ time taken for change
= 5 m/min ÷ (1/6) min
= 30 m/min² (= 0.0833 m/s²)
