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19-10-2016
Physics

contestada

A 30 nc charge experiences a 0.047 n electric force. what is the magnitude of electric field at the position of this charge?

Respuesta :

Edufirst Edufirst

02-11-2016

Electric force = electric field * charge

F = E*C => E = F / C = 0.047 N / 30 nC = 0.00157 N/nC = 0.00157 * 10^9 N/C = 1.57 * 10^6 N/C

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