Answer:
f(x) = (-x + 3)^-1
g(x) = x^-1
h(x) = (-x + 3)
Step-by-step explanation:
We know that:
g(x) ≠ x
h(x) ≠ x
f(x) = g(h(x))
f(x) = (-x + 3)^(-1) = g(h(x))
Then we can define:
h(x) as the thing inside the first parenthesis:
h(x) = (-x + 3)
And g(x) as the function that is evaluated in this, then:
g(x) = x^-1
So when we have:
g(h(x)) = (h(x))^-1 = ( (-x + 3) )^-1 = (-x + 3)^-1
Then we have:
f(x) = (-x + 3)^-1
g(x) = x^-1
h(x) = (-x + 3)
