Answer:
[tex]x_{1}[/tex]=(3+[tex]\sqrt{5}[/tex])/2
[tex]x_{2}[/tex]=(3-[tex]\sqrt{5}[/tex])/2
Step-by-step explanation:
x^2-3x+1=0
[tex]x_{1}[/tex]=(3+[tex]\sqrt{3^2-4*1*1}[/tex])/2=(3+[tex]\sqrt{5}[/tex])/2
[tex]x_{2}[/tex]=(3-[tex]\sqrt{3^2-4*1*1}[/tex])/2=(3-[tex]\sqrt{5}[/tex])/2
