Answer:
Step-by-step explanation:
The standard form of the quadratic we need is
[tex]y=a(x-h)^2+k[/tex] where we have everything we need but a. That's what we will solve for.
x and y come from the coordinate given on the red graph:
x = 2 and y = 1
h and k come from the coordinates of the vertex:
(0, 0). Fill all that in and solve for a:
[tex]1=a(2-0)^2+0[/tex] and
1 = 4a so
a = 1/4 That makes our equation
[tex]y=\frac{1}{4}(x-0)^2+0[/tex] or simplified:
[tex]y=\frac{1}{4}x^2[/tex], choice B.
