domannickedison79
domannickedison79 domannickedison79
  • 18-07-2021
  • Mathematics
contestada

Expand the logarithm as much as possible. Rewrite the expression as a sum, difference, or product of logs.



ln(1/49^k)

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sqdancefan
sqdancefan sqdancefan
  • 18-07-2021

9514 1404 393

Answer:

  -2k·ln(7)

Step-by-step explanation:

49 is a perfect square, so the argument of the log function can be written as ...

  1/46^k = 1/(7^2)^k = 1/7^(2k) = 7^(-2k)

Then the log of it is ...

  ln(7^(-2k)) = -2k·ln(7)

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