ethari20042021
ethari20042021 ethari20042021
  • 19-09-2021
  • Mathematics
contestada

Why the derivative of (x^2/a^2) = (2x/a^2)? ​

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LammettHash
LammettHash LammettHash
  • 21-09-2021

I assume you're referring to a function,

[tex]f(x) = \dfrac{x^2}{a^2}[/tex]

where a is some unknown constant. By definition of the derivative,

[tex]\displaystyle f'(x) = \lim_{h\to0}{f(x+h)-f(x)}h[/tex]

Then

[tex]\displaystyle f'(x) = \lim_{h\to0}{\frac{(x+h)^2}{a^2}-\frac{x^2}{a^2}}h \\\\ f'(x) = \frac1{a^2} \lim_{h\to0}{(x+h)^2-x^2}h \\\\ f'(x) = \frac1{a^2} \lim_{h\to0}{(x^2+2xh+h^2)-x^2}h \\\\ f'(x) = \frac1{a^2} \lim_{h\to0}{2xh+h^2}h \\\\ f'(x) = \frac1{a^2} \lim_{h\to0}(2x+h) = \boxed{\frac{2x}{a^2}}[/tex]

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