Answer:
False, [tex]i^2\neq \sqrt{2}[/tex]
Step-by-step explanation:
[tex]i[/tex] is defined as:
[tex]i=\sqrt{-1}[/tex]
so [tex]i^2[/tex] must be:
[tex]i^2=(\sqrt{-1})^{2}[/tex]
The square root and the squared power are inverse operations, so they cancel ech other
[tex]i^2=-1[/tex]
so it is concluded that [tex]i^2[/tex] is not equal to [tex]\sqrt{2}[/tex], but instead is equal to [tex]-1[/tex]
