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  • 19-12-2021
  • Mathematics
contestada

find n. (n!)²- 4n! - 12 = 0​

Respuesta :

Аноним Аноним
  • 19-12-2021

Answer:

n=6 , n=-2

Step-by-step explanation:

[tex]n^{2}-4n-12=0[/tex]

Factorise to give:

[tex](n-6)(n+2)[/tex]

Set first one to equal 0:

[tex]n-6=0[/tex]

[tex]n=6[/tex]

Set second one to equal 0:

[tex]n+2=0[/tex]

[tex]n=-2[/tex]

Reason for 2 solutions:

All quadratics can have a maximum of 2 solutions like this one or a minimum of 0.

The solution(s) is the point where the graph crosses the x-axis

The image below shows the graph of the equation:

[tex]n^{2}-4n-12[/tex]

When y=0:

It intercepts the x-axis at 6 and -2 giving why n has 2 solutions

Ver imagen Аноним
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