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  • 17-01-2022
  • Chemistry
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1.5 mol CaCO3 in 0.5 L solution. What is the molarity?

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xKelvin
xKelvin xKelvin
  • 17-01-2022

Answer:

[tex]\displaystyle \text{ 3 M}[/tex]

Explanation:

Molarity is given by the ratio of the amount of moles of the solute over the total volume of the solution. That is:

[tex]\displaystyle \text{M} = \frac{\text{ mols solute}}{\text{ L soln.}}[/tex]

Substitute:

[tex]\displaystyle \begin{aligned} \text{M} & = \frac{(1.5\text{ mol CaCO$_3$} ) } { (0.5\text{ L soln.} )} \\ \\ & = 3\text{ M}\end{aligned}[/tex]

In conclusion, the solution is 3 molar.

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