lilsasuke25 lilsasuke25

21-02-2022
Mathematics

contestada

can someone help me with this

can someone help me with this class=

Respuesta :

zsm2800 zsm2800

21-02-2022

Answer:

[tex]\left[\begin{array}{ccc}-6&10\\10&-10\end{array}\right][/tex]

Step-by-step explanation:

[tex]-2A=-2*\left[\begin{array}{ccc}3&-5\\-5&5\end{array}\right]=\left[\begin{array}{ccc}-6&10\\10&-10\end{array}\right][/tex]

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