Respuesta :
[tex] \underline {\huge \boxed{ \sf \color{skyblue}Answer : }}[/tex]
Given :
[tex] \tt \large {\color{purple} ↬ } \: \: \: \: \: I_{D} = 5mA[/tex]
[tex] \: \: [/tex]
[tex] \tt \large {\color{purple} ↬ } \: \: \: \: \: I_{DSS} = 10mA[/tex]
[tex] \: \: [/tex]
[tex] \tt \large {\color{purple} ↬ } \: \: \: \: \: V_{GS(off)} = -6V[/tex]
[tex] \: \: [/tex]
[tex] \tt \large {\color{purple} ↬ } \: \: \: \: \: V_{GS} = {?}[/tex]
[tex] \: \: \: [/tex]
Let's Slove :
- [tex] \tt \large I_{D} = I_{(DSS)} (1 - \frac {V_{GS}}{V_{GS(off)}} )^{2} [/tex]
[tex] \: \: \: [/tex]
- [tex] \tt \large \: V_{GS} = (1 - \frac{ \sqrt{I_D} }{ \sqrt{I_{DSS}} } ) \times V_{GS(off)}[/tex]
[tex] \: \: \: [/tex]
- [tex] \tt \large \: V_{GS} = (1 - \frac{ \sqrt{5m} }{ \sqrt{10m} } ) \times { - 6}[/tex]
[tex] \: \: [/tex]
- [tex] \underline \color{red} {\tt \large \boxed {\tt V_{GS} = 1.75 ✓}}[/tex]