Answer:
x = - [tex]\frac{3}{2}[/tex]
Step-by-step explanation:
[tex]16^{x}[/tex] = [tex]\frac{1}{64}[/tex] , that is
[tex](4^2)^{x}[/tex] = [tex]\frac{1}{4^3}[/tex]
[tex]4^{2x}[/tex] = [tex]4^{-3}[/tex]
since bases on both sides are equal , both 4 then equate exponents
2x = - 3 ( divide both sides by 2 )
x = - [tex]\frac{3}{2}[/tex]
