16-07-2017
Mathematics

contestada

Solve log2(6-2x)-log2x=3

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sergibcnusa sergibcnusa

16-07-2017

Assuming you have log in base 2.

Join logarithms (always):

log2(6-2x)-log2(x) = log2( (6-2x/x) )

Then get rid of it! :)

(6-2x)/x = 2^3=8,

Solve the equation:

6-2x=8x ---> 10x=6 ---> x = 3/5.

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