Find the center and radius of a circle defined by the equation x^2+yy^2+4x-8y+13=0

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16-08-2017
Mathematics

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Find the center and radius of a circle defined by the equation x^2+yy^2+4x-8y+13=0

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ghanami ghanami · Answer 1 · 2017-08-18T11:19:43+02:00

ghanami ghanami

18-08-2017

hello :
x²+y²+4x-8y +13 = 0
(x² +4x) +(y² -8y )+13 = 0
(x²+4x+4) -4 +(y-8y +16) -16 +13 = 0
(x+2)² +(y -4)² = 7
the center is : (-2 , 4) and radius √7

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