The solutions to the equation are [tex] \frac{-5 +/- \sqrt{13}}{6} [/tex]
You can find the answer to any quadratic by using the quadratic formula. The formula is below.
[tex] \frac{-b +/- \sqrt{b^{2}-4ac}}{2a} [/tex]
Then find a (the number attached to x^2), b (the number attached to x) and c (the constant). This will allow you to plug in and solve.
[tex] \frac{-5 +/- \sqrt{5^{2}-4(3)(1)}}{2(3)} [/tex]
[tex] \frac{-5 +/- \sqrt{25-12}}{6} [/tex]
[tex] \frac{-5 +/- \sqrt{13}}{6} [/tex]
