annacruzbhwille annacruzbhwille

17-10-2015
Mathematics

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If y varies directly as the cube of x, what is the value of y in the ordered pairs (4, 16)(2, y)?

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konrad509 konrad509

17-10-2015

[tex]y=kx^3\\\\ 16=k\cdot4^3\\ 64k=16\\ k=\dfrac{16}{64}=\dfrac{1}{4}\\\\ y=\dfrac{1}{4}\cdot2^3\\ y=\dfrac{1}{4}\cdot8\\ \boxed{y=2} [/tex]

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