meme41 meme41
  • 19-06-2014
  • Mathematics
contestada

for a circle of radius 4 with center (-4, 3). in general form

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Ryan2
Ryan2 Ryan2
  • 19-06-2014
Reduced Equation:

[tex](x-x_o)^2+(y-y_o)=r^2\\ \\ (x+4)^2+(y-3)^2=16\\ \\ x^2+8x+16+y^2-6y+9-16=0\\ \\ \boxed{x^2+y^2+8x-6y+9=0}[/tex]
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AL2006
AL2006 AL2006
  • 19-06-2014
I'm going to assume that you're asking for the equation of that circle.
It's

(x + 4)² + (y - 3)² = 16
Answer Link

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