[tex] {x}^{ \frac{2}{3} } - {3x}^{ \frac{1}{3} } - 4 = 0[/tex]
Solve using substitution
[tex] {t}^{2} - 3t - 4 = 0[/tex]
Solve the equation
[tex]t = 4 \\ t = - 1[/tex]
Return the substituted values
[tex] {x}^{ \frac{1}{3} } = 4 \\ {x}^{ \frac{1}{3} } = - 1[/tex]
Solve the equations
[tex]x = 64 \\ x = - 1[/tex]
The final solutions are,
[tex]x1 = - 1 \\ x2 = 64[/tex]
