Respuesta :

konrad509
[tex] -2(x + 3) = -2(x + 1) - 4\\ -2x-6=-2x-2-4\\ -6=-6\\ x\in\mathbb{R}[/tex]
[tex]-2(x+3)=-2(x+1)-4\\\\-2x-6=-2x-2-4\\\\-2x-6=-2x-6\ \ \ \ |add\ (-2x)\ to\ both\ sides\\\\-6=-6\ \ TRUE\\\\ infinitely\ many\ solutions,\ x\in\mathbb{R}.[/tex]
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